For a body in a circular orbit around Earth of radius r, the ratio of …

Question

For a body in a circular orbit around Earth of radius r, the ratio of kinetic energy to total mechanical energy is

Accepted Answer

D. {'text': '1 : (−1)', 'label': 'D'}

1. For a circular orbit: KE = (1/2) m v² = G M m / (2 r).
2. PE = −G M m / r; total energy E = KE + PE = −G M m / (2 r).
3. Compare: KE = −E, so KE / E = −1, or equivalently 1 : (−1).
4. This is the standard virial-theorem relation for gravitational orbits.
_Source: NCERT Class 11 Physics, Ch 7 "Gravitation", §7.7_

Answer

{'text': '1 : 1', 'label': 'A'}

Answer

{'text': 'Undefined', 'label': 'B'}

Answer

{'text': '2 : (−1)', 'label': 'C'}