The acceleration due to gravity g at height h above Earth's surface (radius R) is approximately
Ag × (R + h)
Bg × (1 + 2h/R)
Cg × (1 − 2h/R)
Dg × (R − h)
Answer & Solution
Correct answer: C. g × (1 − 2h/R)
1. g_h = g × R² / (R + h)².
2. For h ≪ R, expand: (1 + h/R)⁻² ≈ 1 − 2h/R.
3. So g_h ≈ g × (1 − 2h/R) to first order.
4. This is the fractional decrease in g as we rise above Earth's surface.
_Source: syllabus Physics, Ch 7 "Gravitation", §7.4_
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