An orbiting satellite has an orbital speed v = √(G M / r). If the orbital radius r is quadrupled, the new speed is
Av
B2v
Cv/2
D4v
Answer & Solution
Correct answer: C. v/2
1. Orbital speed v = √(G M / r), so v ∝ 1/√r.
2. New r = 4r; new v = √(G M / 4r) = √(G M / r) / 2 = v/2.
3. Higher orbits have lower speeds but longer periods (Kepler's third law).
4. This is consistent with slower motion for outer planets like Neptune.
_Source: syllabus Physics, Ch 7 "Gravitation", §7.6_
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