Start learning →

JEE Main Unit 3A1: Gas Laws & Kinetic Molecular Theory — practice questions

Explore 6 free Unit 3A1: Gas Laws & Kinetic Molecular Theory questions in JEE Main Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

Practise Unit 3A1: Gas Laws & Kinetic Molecular Theory with Quill →

Unit 3A1: Gas Laws & Kinetic Molecular Theory questions and exercises with answers

Showing questions 1–6 of 6.

Worked practice questions

The ideal gas equation of state is:

  1. $PV = RT$
  2. $PV = nRT$
  3. $P + V = nRT$
  4. $\dfrac{P}{V} = nRT$
Show answer and solution

Correct answer: B. $PV = nRT$

Ideal gas law: $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is moles, $R$ is the universal gas constant ($8.314$ J/(mol·K) or $0.0821$ L·atm/(mol·K)), and $T$ is absolute temperature in Kelvin. This equation combines Boyle's law ($PV =$ const at fixed $T, n$), Charles's law ($V/T =$ const at fixed $P, n$), and Avogadro's hypothesis ($V/n =$ const at fixed $T, P$) into one statement.

Open this question →

Boyle's law for a fixed amount of gas at constant temperature states that:

  1. Pressure is directly proportional to volume
  2. $P^2 V = $ constant
  3. Pressure is inversely proportional to volume
  4. Volume is independent of pressure
Show answer and solution

Correct answer: C. Pressure is inversely proportional to volume

Boyle's law: at fixed $T$ and $n$, $PV = $ constant, so $P \propto 1/V$. Squeeze a gas into half the volume at constant temperature and its pressure doubles. The $P$-$V$ curve at fixed $T$ is a hyperbola called an isotherm. Option A is the opposite (direct proportion), which would mean compressing a gas reduces its pressure — physically absurd.

Open this question →

Charles's law for a fixed amount of gas at constant pressure states that:

  1. $V \propto T^2$
  2. $V$ is independent of $T$
  3. $V \propto T$ (Kelvin)
  4. $V \propto 1/T$
Show answer and solution

Correct answer: C. $V \propto T$ (Kelvin)

Charles's law: at fixed $P$ and $n$, volume is directly proportional to absolute temperature ($T$ in Kelvin): $V/T = $ constant. Double the Kelvin temperature, double the volume. The key subtlety is that $T$ must be in Kelvin, not Celsius — Charles's law fails badly if you use Celsius (a gas at $0°$C has nonzero volume). Graphically, $V$ vs $T$ (Kelvin) is a straight line passing through the origin.

Open this question →

How to practise

  1. Choose a Unit 3A1: Gas Laws & Kinetic Molecular Theory question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

Put it into practice

Continue with Unit 3A1: Gas Laws & Kinetic Molecular Theory practice for JEE Main. Read explanations as you go. No signup form needed to start.

Practise Unit 3A1: Gas Laws & Kinetic Molecular Theory →

More Chemistry topics