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JEE Advanced Unit 4A1: Types of Chemical Reactions — practice questions

Explore 48 free Unit 4A1: Types of Chemical Reactions questions in JEE Advanced Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 4A1: Types of Chemical Reactions questions and exercises with answers

Showing questions 1–30 of 48.

In the galvanic cell description, which process is correctly identified as oxidation at the zinc electrode?Read the answer and worked solution →Number of moles of KMnO₄ required to oxidize 1 mole of Fe²⁺ in acidic solution:Read the answer and worked solution →Electronic configuration of Cr³⁺ (Z = 24):Read the answer and worked solution →Among Cu, Zn, Pt, Au, which is the noble metal MOST resistant to corrosion?Read the answer and worked solution →pH of 10⁻⁸ M HCl solution (in water):Read the answer and worked solution →In octahedral complex with d⁵ metal and strong field ligand, magnetic moment:Read the answer and worked solution →Number of stereoisomers of 2-bromobutane:Read the answer and worked solution →Which is the strongest oxidizer in halogens?Read the answer and worked solution →Order of basicity: NH₃, PH₃, AsH₃, SbH₃:Read the answer and worked solution →Number of σ and π bonds in CO₂:Read the answer and worked solution →For first-order reaction with t₁/₂ = 10 min, k =Read the answer and worked solution →Among NH₃, PH₃, H₂O, H₂S — most acidic:Read the answer and worked solution →Color of [Cu(NH₃)₄]²⁺:Read the answer and worked solution →Which gives positive iodoform test?Read the answer and worked solution →For coordination compound [Co(NH₃)₅Cl]Br₂, total ions in solution:Read the answer and worked solution →Number of moles of O₂ needed to completely oxidize 1 mole of C₂H₅OH to CO₂ and H₂O:Read the answer and worked solution →Crystal field stabilization energy (CFSE) for [Co(NH₃)₆]³⁺ (Co³⁺ d⁶ low-spin):Read the answer and worked solution →Standard enthalpy of formation of an element in its standard state:Read the answer and worked solution →Bond order of N₂:Read the answer and worked solution →Hybridization of P in PCl₅:Read the answer and worked solution →What does Fehling's solution test detect?Read the answer and worked solution →In an experiment, length = 2.54 cm, radius = 0.25 cm. The volume of the cylinder with proper significant figures is:Read the answer and worked solution →Using dimensional analysis, find the correct relation for time period $T$ of a simple pendulum:Read the answer and worked solution →The dimensional formula of angular momentum per unit mass is:Read the answer and worked solution →The number of significant figures in 0.00250 is:Read the answer and worked solution →1 light year is a unit of:Read the answer and worked solution →The dimensional formula of pressure is:Read the answer and worked solution →Which of the following is a fundamental quantity?Read the answer and worked solution →In the expression $F = \frac{Gm_1m_2}{r^2}$, the dimensional formula of $G$ is:Read the answer and worked solution →The error in the measurement of radius of a sphere is 2%. The error in the measurement of volume is:Read the answer and worked solution →

Worked practice questions

In the galvanic cell description, which process is correctly identified as oxidation at the zinc electrode?

  1. $Zn^{2+} + 2e^- \rightarrow Zn$
  2. $Zn \rightarrow Zn^{2+} + 2e^-$
  3. $Cu^{2+} + 2e^- \rightarrow Cu$
  4. $SO_4^{2-} \rightarrow SO_4 + 2e^-$
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Correct answer: B. $Zn \rightarrow Zn^{2+} + 2e^-$

Oxidation is loss of electrons or increase in oxidation number. At the zinc electrode, zinc metal loses two electrons to form $Zn^{2+}$, so $Zn \rightarrow Zn^{2+} + 2e^-$ is the oxidation half-reaction.

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Number of moles of KMnO₄ required to oxidize 1 mole of Fe²⁺ in acidic solution:

  1. 2
  2. 5
  3. 1/5 (Mn(VII) → Mn(II): 5e⁻ accepted; Fe²⁺ → Fe³⁺: 1e⁻ lost)
  4. 1
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Correct answer: C. 1/5 (Mn(VII) → Mn(II): 5e⁻ accepted; Fe²⁺ → Fe³⁺: 1e⁻ lost)

MnO₄⁻ + 5 e⁻ → Mn²⁺. Fe²⁺ → Fe³⁺ + e⁻. **So 1 MnO₄⁻ oxidizes 5 Fe²⁺ → 1/5 mole KMnO₄ per mole Fe²⁺.**

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Electronic configuration of Cr³⁺ (Z = 24):

  1. [Ar] 3d⁴
  2. [Ar] 3d³
  3. [Ar] 3d⁵
  4. [Ar] 3d⁵ 4s¹
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Correct answer: B. [Ar] 3d³

**Cr:** [Ar] 3d⁵ 4s¹. Cr³⁺: lose 4s and two 3d → [Ar] 3d³. Three unpaired electrons. Paramagnetic.

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