The dimensional formula of angular momentum per unit mass is:
A$[\mathrm{M}^{0}\mathrm{L}^{2}\mathrm{T}^{-1}]$
B$[\mathrm{M}^{0}\mathrm{L}\mathrm{T}^{-1}]$
C$[\mathrm{MLT}^{-1}]$
D$[\mathrm{ML}^{2}\mathrm{T}^{-2}]$
Answer & Solution
Correct answer: A. $[\mathrm{M}^{0}\mathrm{L}^{2}\mathrm{T}^{-1}]$
Angular momentum has dimensions $[ML^2T^{-1}]$. Dividing by mass removes $M$, leaving $[M^0L^2T^{-1}]$.
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