alleryStart learning →In [Cu(NH3)4]²⁺ what is the oxidation number of Cu?
- +3
- +2
- +1
- 0
Show answer and solution
Correct answer: B. +2
NH3 is neutral.
Complex charge is +2. So Cu oxidation state = +2 + 0 - 0 = +2. (Cu²⁺ ion with 4 NH3 ligands.)
Indian Navy AA (Artificer Apprentice) Coordination Compounds — practice questions
Explore 29 free Coordination Compounds questions in Indian Navy AA (Artificer Apprentice) Chemistry. Open each question or exercise to read its content, reference answers and available explanation.
Practise Coordination Compounds with Quill →Coordination Compounds questions and exercises with answers
Showing questions 1–29 of 29.
In [Cu(NH3)4]²⁺ what is the oxidation number of Cu?Read the answer and worked solution →Isomerism where ligands occupy different positions in a square planar complex:Read the answer and worked solution →Number of unpaired electrons in [Co(NH₃)₆]³⁺ (Co³⁺ is d⁶, strong field NH₃ → low spin):Read the answer and worked solution →Sort each ligand by how many donor atoms it usesRead the answer and worked solution →Match each term to its definitionRead the answer and worked solution →True or false: coordination numberRead the answer and worked solution →Counting the coordination numberRead the answer and worked solution →Match each complex to its shapeRead the answer and worked solution →Sort each complex by its geometryRead the answer and worked solution →Complete the coordination sphere ruleRead the answer and worked solution →True or false: ambidentate ligandsRead the answer and worked solution →Chelate or ambidentate?Read the answer and worked solution →Complete the definition of oxidation numberRead the answer and worked solution →Match each theory to what it explainsRead the answer and worked solution →Tap every failing of Valence Bond TheoryRead the answer and worked solution →True or false: the theories and their limitsRead the answer and worked solution →Complete Werner's postulateRead the answer and worked solution →Synergic bonding in metal carbonylsRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Order the steps: read a formula like K₄[Fe(CN)₆]Read the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Tap every statement true of a chelate complexRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →True or false: where coordination chemistry mattersRead the answer and worked solution →Inside the brackets or outside?Read the answer and worked solution →Spot the odd one outRead the answer and worked solution →
Worked practice questions
Isomerism where ligands occupy different positions in a square planar complex:
- Optical
- Geometric (cis-trans)
- Linkage
- Ionization
Show answer and solution
Correct answer: B. Geometric (cis-trans)
Square planar MA₂B₂ has cis (A's adjacent) and trans (A's opposite) isomers.
**Famous example:** cisplatin [PtCl₂(NH₃)₂] (anticancer drug) vs transplatin (inactive).
Number of unpaired electrons in [Co(NH₃)₆]³⁺ (Co³⁺ is d⁶, strong field NH₃ → low spin):
- 6
- 4
- 2
- 0 (low spin d⁶: t₂g⁶, all paired)
Show answer and solution
Correct answer: D. 0 (low spin d⁶: t₂g⁶, all paired)
Co³⁺ = d⁶.
NH₃ borderline (strong enough with Co³⁺) → low spin: t₂g⁶ e_g⁰.
All paired, diamagnetic, μ = 0. (CN⁻ would also give low spin; F⁻ would give high spin.)
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