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Indian Navy AA (Artificer Apprentice) Chemical Equilibrium — practice questions

Explore 62 free Chemical Equilibrium questions in Indian Navy AA (Artificer Apprentice) Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Chemical Equilibrium questions and exercises with answers

Showing questions 1–30 of 62.

The hydrogen spectral lines that lie in the visible region of the electromagnetic spectrum belong to the:Read the answer and worked solution →For the reaction N2 + 3H2 ⇌ 2NH3, increasing pressure favours:Read the answer and worked solution →At 500 K, Kc for N2 + 3H2 ⇌ 2NH3 is 60 (in mol⁻² L²). Kp at 500 K (R = 0.0821):Read the answer and worked solution →For the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g), if initial pressure of PCl5 is P0 and degree of dissociation is α, total pressure at equilibrium:Read the answer and worked solution →If K = 1 for a reaction, the standard free energy change ΔG°:Read the answer and worked solution →The bond order of the oxygen molecule O₂ (by molecular orbital theory) isRead the answer and worked solution →As per your syllabus, adding an INERT gas (e.g. argon) at CONSTANT VOLUME to a gaseous equilibrium has what effect?Read the answer and worked solution →As per your syllabus, eqn 6.29, at 298 K, what is the value of pH + pOH for any aqueous solution?Read the answer and worked solution →As per your syllabus, when [salt] = [acid] in a buffer, the pH of the buffer equals which quantity?Read the answer and worked solution →CLASS10 · Chemistry · Periodic Table Trends — Gap FillRead the answer and worked solution →Sodium (atomic number 11) belongs to which group and period?Read the answer and worked solution →Which of the following elements will form an acidic oxide?Read the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →The fundamental particlesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →

Worked practice questions

The hydrogen spectral lines that lie in the visible region of the electromagnetic spectrum belong to the:

  1. Lyman series
  2. Paschen series
  3. Pfund series
  4. Balmer series
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Correct answer: D. Balmer series

Balmer series corresponds to transitions terminating in $n_1 = 2$. The first four lines ($n_2 = 3, 4, 5, 6$ to $n_1 = 2$) lie at approximately $656\,\text{nm}$ (H$_\alpha$, red), $486\,\text{nm}$ (H$_\beta$, blue-green), $434\,\text{nm}$ (H$_\gamma$, blue) and $410\,\text{nm}$ (H$_\delta$, violet), all in the visible range.

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For the reaction N2 + 3H2 ⇌ 2NH3, increasing pressure favours:

  1. Forward (fewer moles on RHS)
  2. Random direction
  3. No effect
  4. Reverse
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Correct answer: A. Forward (fewer moles on RHS)

Reactants have 4 moles of gas (1 N2 + 3 H2), products have 2 moles (2 NH3). Increasing pressure shifts equilibrium toward fewer moles, hence toward products. This is the basis of Haber's process.

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At 500 K, Kc for N2 + 3H2 ⇌ 2NH3 is 60 (in mol⁻² L²). Kp at 500 K (R = 0.0821):

  1. 60
  2. 60/(RT)²
  3. 60 × (RT)
  4. 60 × (RT)²
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Correct answer: B. 60/(RT)²

Δn_gas = 2 - 4 = -2. Kp = Kc (RT)^Δn = 60 × (0.0821 × 500)⁻² = 60 / (41.05)² ≈ 0.036 atm⁻².

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