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Number of unpaired electrons in [Co(NH₃)₆]³⁺ (Co³⁺ is d⁶, strong field NH₃ → low spin):
A6
B4
C2
D0 (low spin d⁶: t₂g⁶, all paired)
Answer & Solution
Correct answer: D. 0 (low spin d⁶: t₂g⁶, all paired)
Co³⁺ = d⁶. NH₃ borderline (strong enough with Co³⁺) → low spin: t₂g⁶ e_g⁰. All paired, diamagnetic, μ = 0. (CN⁻ would also give low spin; F⁻ would give high spin.)
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