Start learning →

Number of unpaired electrons in [Co(NH₃)₆]³⁺ (Co³⁺ is d⁶, strong field NH₃ → low spin):

A6
B4
C2
D0 (low spin d⁶: t₂g⁶, all paired)
Answer & Solution
Correct answer: D. 0 (low spin d⁶: t₂g⁶, all paired)
Co³⁺ = d⁶. NH₃ borderline (strong enough with Co³⁺) → low spin: t₂g⁶ e_g⁰. All paired, diamagnetic, μ = 0. (CN⁻ would also give low spin; F⁻ would give high spin.)
Practise this question with Quill — JEE Advanced →

Keep practising Unit 2B1: Transition Metals & Coordination Compounds

Browse all Unit 2B1: Transition Metals & Coordination Compounds questions for JEE Advanced, or explore more Chemistry topics.

Start a Unit 2B1: Transition Metals & Coordination Compounds lesson →