alleryFor first-order, integrated rate law:
Aln([A]₀/[A]) = kt
B[A]₀ - [A] = kt
C1/[A] - 1/[A]₀ = kt
D[A] = constant
Answer & Solution
Correct answer: A. ln([A]₀/[A]) = kt
d[A]/dt = -k[A] integrates to ln([A]₀/[A]) = kt, or [A] = [A]₀ e^(-kt). Exponential decay.
Plot ln[A] vs t is straight line with slope -k.
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