tan(A + B) equals:
- tanA + tanB
- tanA tanB
- (tanA + tanB)/(1 - tanA tanB)
- (tanA - tanB)/(1 + tanA tanB)
Show answer and solution
Correct answer: C. (tanA + tanB)/(1 - tanA tanB)
tan(A + B) = (tanA + tanB)/(1 - tanA tanB).
*Note: when tanA tanB = 1, denominator is 0 — that's when A + B = 90° + 180°k.*