allerytan(A + B) equals:
AtanA + tanB
BtanA tanB
C(tanA + tanB)/(1 - tanA tanB)
D(tanA - tanB)/(1 + tanA tanB)
Answer & Solution
Correct answer: C. (tanA + tanB)/(1 - tanA tanB)
tan(A + B) = (tanA + tanB)/(1 - tanA tanB).
*Note: when tanA tanB = 1, denominator is 0 — that's when A + B = 90° + 180°k.*
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