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In triangle ABC with sides a, b, c opposite to angles A, B, C: sine rule states:

Aa/sinA = b/sinB = c/sinC
Ba + b + c = 0
CsinA = sinB
Da²+b² = c²
Answer & Solution
Correct answer: A. a/sinA = b/sinB = c/sinC
**Sine rule:** a/sinA = b/sinB = c/sinC = 2R (where R is circumradius). Useful for solving triangles when you know any side + opposite angle + one more piece.
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