General solution of cos θ = 0:
Aθ = π/2 + nπ
Bθ = nπ
Cθ = π/4 + nπ
Dθ = 0 + 2nπ
Answer & Solution
Correct answer: A. θ = π/2 + nπ
cos θ = 0 at θ = π/2 and 3π/2 (i.e., 90° and 270°). General: θ = π/2 + nπ where n ∈ ℤ. (Every π apart.)
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