sin(180° - θ) equals:
Acos θ
B-cos θ
C-sin θ
Dsin θ
Answer & Solution
Correct answer: D. sin θ
sin is positive in Q2: sin(180° - θ) = sin θ. (Compare: cos(180° - θ) = -cos θ; tan(180° - θ) = -tan θ.)
Related questions
If cos θ = −1/2 and θ ∈ (π, 3π/2), then θ equals:tan(45° + θ) · tan(45° − θ) is equal to:sin 75° equals:By the law of sines in a triangle, a / sin A is equal to:The general solution of cos x = 0 is:The general solution of sin x = 0 is:If sin θ = 3/5 and θ is acute, then cos θ equals:The angle in radians for 120° is: