The train slows from 30.0 km/h to a stop in 8.00 s. Its acceleration is about:
- +1.04 m/s squared
- -3.75 m/s squared
- -0.42 m/s squared
- -1.04 m/s squared
Show answer and solution
Correct answer: D. -1.04 m/s squared
1. Convert 30 km/h to m/s first.
2. The change divided by 8.00 s gives about -1.04.
3. The minus sign shows it opposes the motion.
_Source: OpenStax College Physics for AP Courses 2e, Chapter 2, Kinematics (CC BY 4.0)._