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The train slows from 30.0 km/h to a stop in 8.00 s. Its acceleration is about:

A+1.04 m/s squared
B-3.75 m/s squared
C-0.42 m/s squared
D-1.04 m/s squared
Answer & Solution
Correct answer: D. -1.04 m/s squared
1. Convert 30 km/h to m/s first. 2. The change divided by 8.00 s gives about -1.04. 3. The minus sign shows it opposes the motion. _Source: OpenStax College Physics for AP Courses 2e, Chapter 2, Kinematics (CC BY 4.0)._
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