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A 3 Ω resistor is connected in series with a parallel combination of a 6 Ω and a 3 Ω resistor. The equivalent resistance of the network is:
A4 Ω
B5 Ω
C9 Ω
D12 Ω
Answer & Solution
Correct answer: B. 5 Ω
6 Ω ∥ 3 Ω = (6×3)/(6+3) = 2 Ω; this in series with 3 Ω gives 2 + 3 = 5 Ω.
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