Home › AP Intermediate 2nd Year › Physics › Current Electricity › Two 100-W bulbs are connected in series across 2…
Two 100-W bulbs are connected in series across 220 V. The total power consumed is:
A50 W
B100 W
C200 W
D400 W
Answer & Solution
Correct answer: A. 50 W
1. Each 100-W bulb at 220 V has R = V²/P = 220²/100 = 484 Ω.
2. In series, total R = 2 × 484 = 968 Ω; voltage 220 V gives I = 220/968 ≈ 0.227 A.
3. Total power = V·I = 220 × 0.227 ≈ 50 W.
4. In series, two identical bulbs share half their normal voltage each → ¼ rated power each → 50 W total.
_Source: NCERT Class 12 Physics Ch 3 §3.10 (combinations and power)_
Related questions
The reactance of a capacitor $C$ at frequency $f$ in an a.c. circuit is:A bird perched on a single high voltage wire is unharmed because:The two conservation laws embodied in Kirchhoff's rules are conservation of:The resistance offered by the cell itself is called:Which device detects the current in a Wheatstone bridge?In a Wheatstone bridge, the source is connected across the:The Wheatstone bridge is made up of how many resistors?At a junction, the current entering equals the current: