Two 100-W bulbs are connected in series across 220 V. The total power consumed is:

1. Each 100-W bulb at 220 V has R = V²/P = 220²/100 = 484 Ω. 2. In series, total R = 2 × 484 = 968 Ω; voltage 220 V gives I = 220/968 ≈ 0.227 A. 3. Total power = V·I = 220 × 0.227 ≈ 50 W. 4. In series, two identical bulbs share half their normal voltage each → ¼ rated power each → 50 W total. _Source: syllabus Physics Ch 3 §3.10 (combinations and power)_