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Two identical cells, each of emf 1.5 V and internal resistance 0.5 Ω, are connected in parallel across a 1 Ω resistor. The current through the resistor is:

A0.6 A
B1.2 A
C3.0 A
D1.5 A
Answer & Solution
Correct answer: B. 1.2 A
Identical cells in parallel: ε_eq = 1.5 V, r_eq = 0.5/2 = 0.25 Ω We have I = 1.5/(1 + 0.25). So I = 1.2 A.
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