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AP Intermediate 2nd Year Haloalkanes, Alcohols and Ethers — practice questions — page 2

Explore 74 free Haloalkanes, Alcohols and Ethers questions in AP Intermediate 2nd Year Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Haloalkanes, Alcohols and Ethers questions and exercises with answers

Showing questions 31–60 of 74.

The KOLBE reaction converts phenol (in the form of sodium phenoxide) into salicylic acid. The conditions and key reagent areRead the answer and worked solution →Haloalkanes are compounds derived from alkanes byRead the answer and worked solution →$\mathrm{(CH_3)_3CCl}$ is classified as aRead the answer and worked solution →The reactivity order for the $\mathrm{S_N 1}$ mechanism among haloalkanes isRead the answer and worked solution →The WURTZ REACTION couples two alkyl halides with sodium metal in dry ether to giveRead the answer and worked solution →The reactivity of haloalkanes toward nucleophilic substitution generally follows the orderRead the answer and worked solution →A SN2 reaction on a chiral carbon (with a single stereocentre) results inRead the answer and worked solution →The IUPAC name of $\mathrm{(CH_3)_2CH{-}CH_2Br}$ isRead the answer and worked solution →A GRIGNARD REAGENT is formed by reacting an alkyl halide withRead the answer and worked solution →NEET · Chemistry · Primary or Secondary AlcoholRead the answer and worked solution →NEET · Chemistry · SN1 or SN2Read the answer and worked solution →Fix the wrong word on halide reactionsRead the answer and worked solution →Sort each clue into SN1 or SN2Read the answer and worked solution →Match each named reactionRead the answer and worked solution →Sort the SN1 and SN2 traitsRead the answer and worked solution →Swipe by the carbon holding XRead the answer and worked solution →Spot the false claimRead the answer and worked solution →Pick the bigger halide valueRead the answer and worked solution →Alcohol, phenol or ether?Read the answer and worked solution →True or false: alcohols and phenolsRead the answer and worked solution →The WURTZ REACTION couples two alkyl halides with sodium metal in dry ether to giveRead the answer and worked solution →The reactivity order for the $\mathrm{S_N 1}$ mechanism among haloalkanes isRead the answer and worked solution →NEET · Chemistry · SN1 or SN2Read the answer and worked solution →A SN2 reaction on a chiral carbon (with a single stereocentre) results inRead the answer and worked solution →$\mathrm{(CH_3)_3CCl}$ is classified as aRead the answer and worked solution →Haloalkanes are compounds derived from alkanes byRead the answer and worked solution →True or false: alcohols and phenolsRead the answer and worked solution →The Williamson ether synthesis works best with:Read the answer and worked solution →Phenol reacts with bromine WATER (aqueous $\mathrm{Br_2}$) at room temperature to giveRead the answer and worked solution →Alcohol, phenol or ether?Read the answer and worked solution →

Worked practice questions

The KOLBE reaction converts phenol (in the form of sodium phenoxide) into salicylic acid. The conditions and key reagent are

  1. $\mathrm{CO_2}$ under pressure
  2. $\mathrm{CHCl_3}$ + NaOH
  3. $\mathrm{Br_2}$ in $\mathrm{CS_2}$
  4. $\mathrm{H_2SO_4}$ at $443\,\text{K}$
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Correct answer: A. $\mathrm{CO_2}$ under pressure

1. Your syllabus: KOLBE reaction (also Kolbe-Schmitt) introduces a carboxylic acid group onto the phenoxide. 2. PROCEDURE: sodium phenoxide is heated with $\mathrm{CO_2}$ under PRESSURE (~125°C, ~4 atm), then ACIDIFIED. 3. MECHANISM: the phenoxide ion (activated nucleophile, with negative charge delocalised to ortho/para) attacks CO$_2$ at the ortho position. After workup with acid, the product is ORTHO-hydroxybenzoic acid (SALICYLIC ACID). 4. PRODUCT: salicylic acid is the precursor of ASPIRIN (acetylsalicylic acid) — historically important industrial chemistry. 5. Option B describes the REIMER-TIEMANN reaction (gives aldehyde, not acid). Option C is mild bromination (gives bromophenol). Option D is dehydration of alcohol, unrelated. _Source: syllabus Chemistry Part 2, Ch 7, §7.7 (Kolbe reaction), p. 18–19._

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Haloalkanes are compounds derived from alkanes by

  1. replacing one or more hydrogen atoms with halogen atoms
  2. adding $\mathrm{OH}$ groups to the chain
  3. removing the terminal carbon
  4. converting all C-H bonds to C-O bonds
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Correct answer: A. replacing one or more hydrogen atoms with halogen atoms

1. Your syllabus: a haloalkane (alkyl halide) is an alkane in which one or more H atoms have been replaced by HALOGEN atoms (F, Cl, Br, or I). 2. General formula for monohaloalkanes: $\mathrm{C_nH_{2n+1}X}$, where X is the halogen. 3. Examples: $\mathrm{CH_3Cl}$ (chloromethane), $\mathrm{CH_3CH_2Br}$ (bromoethane), $\mathrm{(CH_3)_3CCl}$ (tert-butyl chloride). 4. Distinct from haloarenes (where the halogen is attached to an aromatic ring — e.g. $\mathrm{C_6H_5Cl}$ chlorobenzene). 5. Options B (alcohols), C (chain shortening), D (over-oxidation) describe different transformations. _Source: syllabus Chemistry Part 2, Ch 6 "Haloalkanes and Haloarenes", §6.1 (Classification), p. 1._

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$\mathrm{(CH_3)_3CCl}$ is classified as a

  1. primary (1°) haloalkane
  2. secondary (2°) haloalkane
  3. tertiary (3°) haloalkane
  4. vinyl halide
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Correct answer: C. tertiary (3°) haloalkane

1. Your syllabus: haloalkanes are classified by the type of carbon bearing the halogen. 2. PRIMARY: the carbon attached to halogen is connected to ONE other carbon. SECONDARY: two. TERTIARY: three. 3. In $\mathrm{(CH_3)_3CCl}$, the C bonded to Cl is connected to THREE other carbons (three methyl groups). 4. So this is a TERTIARY (3°) haloalkane. Common name: tert-butyl chloride; IUPAC: 2-chloro-2-methylpropane. 5. Tertiary haloalkanes favour SN1 mechanisms (stable tertiary carbocations). 6. Options A and B are wrong substitution counts. Option D requires C=C adjacent to the halogen, not present here. _Source: syllabus Chemistry Part 2, Ch 6, §6.1 (Classification — 1°/2°/3°), p. 1–2._

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