Home › UP Board Class 12 › chemistry › Haloalkanes and Haloarenes › $\mathrm{(CH_3)_3CCl}$ is classified as a
$\mathrm{(CH_3)_3CCl}$ is classified as a
Aprimary (1°) haloalkane
Bsecondary (2°) haloalkane
Ctertiary (3°) haloalkane
Dvinyl halide
Answer & Solution
Correct answer: C. tertiary (3°) haloalkane
1. NCERT §6.1: haloalkanes are classified by the type of carbon bearing the halogen.
2. PRIMARY: the carbon attached to halogen is connected to ONE other carbon. SECONDARY: two. TERTIARY: three.
3. In $\mathrm{(CH_3)_3CCl}$, the C bonded to Cl is connected to THREE other carbons (three methyl groups).
4. So this is a TERTIARY (3°) haloalkane. Common name: tert-butyl chloride; IUPAC: 2-chloro-2-methylpropane.
5. Tertiary haloalkanes favour SN1 mechanisms (stable tertiary carbocations).
6. Options A and B are wrong substitution counts. Option D requires C=C adjacent to the halogen, not present here.
_Source: NCERT Class 12 Chemistry Part 2, Ch 6, §6.1 (Classification — 1°/2°/3°), p. 1–2._
Related questions
$\mathrm{CHCl_3}$ (chloroform) on prolonged storage in the air may be partially oxidised tChlorobenzene ($\mathrm{C_6H_5Cl}$) is MUCH LESS reactive toward nucleophilic substitutionSAYTZEFF'S RULE for elimination reactions states thatWhen 1-bromopropane is heated with concentrated alcoholic KOH, the major product isA GRIGNARD REAGENT is formed by reacting an alkyl halide withThe IUPAC name of $\mathrm{(CH_3)_2CH{-}CH_2Br}$ isA SN2 reaction on a chiral carbon (with a single stereocentre) results inThe reactivity of haloalkanes toward nucleophilic substitution generally follows the order