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Force on a current-carrying conductor of length l in magnetic field B (perpendicular):

AF = B/I
BF = l/B
CF = BI
DF = BIl
Answer & Solution
Correct answer: D. F = BIl
F = BIL (in vector form F = IL × B). When current perpendicular to field, magnitude F = BIL. **When parallel:** F = 0. Foundation of motor action — torque on coil in field.
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