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Full-wave bridge rectifier with input V_m sin(ωt), DC output:
AV_m
B2V_m/π (≈ 0.637 V_m) — both half-cycles inverted to positive
CV_m/π
D0
Answer & Solution
Correct answer: B. 2V_m/π (≈ 0.637 V_m) — both half-cycles inverted to positive
Bridge rectifier: 4 diodes, both half-cycles → positive. V_avg = 2V_m/π. RMS: V_m/√2. Ripple lower than half-wave (γ = 0.482). With capacitor filter, ripple further reduced. Most common power supply topology.
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