Two-wattmeter method measures 3-phase power. Total power:
AW1 × W2
BAlgebraic sum: P = W1 + W2 (regardless of pf)
CJust W1
DW1 + W2
Answer & Solution
Correct answer: B. Algebraic sum: P = W1 + W2 (regardless of pf)
**Two-wattmeter method:** connect 2 wattmeters to any two lines (current coil) and remaining line (potential coil).
Algebraic sum gives total 3-phase power.
Works for any balance/unbalance.
tan φ = √3(W1-W2)/(W1+W2) gives load power factor.
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