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Two capacitors C1 and C2 in series. Equivalent capacitance:
AC1 + C2
BC1 - C2
CC1 C2/(C1 + C2) (reciprocals add: 1/C_eq = 1/C1 + 1/C2)
DC1 × C2
Answer & Solution
Correct answer: C. C1 C2/(C1 + C2) (reciprocals add: 1/C_eq = 1/C1 + 1/C2)
Capacitors in series: 1/C_eq = Σ(1/C_i). Like resistors in parallel. Two in series: C_eq = C1C2/(C1+C2). Voltage divides inversely proportional to C. Charge same on each.
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