Two capacitors C1 and C2 in series. Equivalent capacitance:

Question

Accepted Answer

C. C1 C2/(C1 + C2) (reciprocals add: 1/C_eq = 1/C1 + 1/C2)

**Capacitors in series:** 1/C_eq = Σ(1/C_i).
Like resistors in parallel.
**Two in series:** C_eq = C1C2/(C1+C2).
Voltage divides inversely proportional to C. Charge same on each.

Answer

C1 + C2

Answer

C1 - C2

Answer

C1 × C2

Two capacitors C1 and C2 in series. Equivalent capacitance:

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