Home › GATE EE › Electrical Engineering › Electrical Circuits & Fundamentals › Impedance of series RLC circuit:
Impedance of series RLC circuit:
AJust X
BZ = √(R² + (X_L - X_C)²) ; phase angle tan φ = (X_L - X_C)/R
CR only
DR + L + C
Answer & Solution
Correct answer: B. Z = √(R² + (X_L - X_C)²) ; phase angle tan φ = (X_L - X_C)/R
Series RLC: Z = R + j(X_L - X_C). |Z| = √(R² + (X_L - X_C)²). Phase: arctan((X_L - X_C)/R). If X_L > X_C: inductive (V leads I). If X_C > X_L: capacitive. If X_L = X_C: resonance.
Related questions
For sinusoidal v(t) = V_m cos(ωt), peak-to-peak value:Two-wattmeter method measures 3-phase power. Total power:RL time constant:Energy density in magnetic field B is:In a 3-phase transmission line, line voltage rms is 415 V. Phase voltage (Y/star) is:Force on a current-carrying conductor of length l in magnetic field B (perpendicular):Full-wave bridge rectifier with input V_m sin(ωt), DC output:For a half-wave rectifier with input V_m sin(ωt), DC output (avg) is: