Dimension of electric field E:
AMA
BML²
CDimensionless
DMLT⁻³A⁻¹ (= force/charge = MLT⁻²/AT = MLT⁻³A⁻¹)
Answer & Solution
Correct answer: D. MLT⁻³A⁻¹ (= force/charge = MLT⁻²/AT = MLT⁻³A⁻¹)
E = F/q. [F] = MLT⁻², [q] = AT (current × time). [E] = MLT⁻² /AT = MLT⁻³A⁻¹. Also = V/m.
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