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Drop of radius R splits into 8 drops of equal size. Each new radius:
AR/2 (since V ∝ r³, 8 drops × (R/2)³ = R³)
BR
CR/4
DR/8
Answer & Solution
Correct answer: A. R/2 (since V ∝ r³, 8 drops × (R/2)³ = R³)
Volume conserved: (4/3)πR³ = 8 × (4/3)π r³ → r = R/2. Surface area increase: 8 × 4π(R/2)² = 8π R². Original: 4π R². So area doubled. Energy needed: γ × (extra area).
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