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Density of mercury 13.6 × 10³ kg/m³. Atmospheric pressure equivalent in mercury column:

A100 cm
B76 cm
CCannot determine
D760 mm (≈ 1 atm)
Answer & Solution
Correct answer: D. 760 mm (≈ 1 atm)
P_atm ≈ 1.013 × 10⁵ Pa. We have h = P/(ρg). That is h = 1.013e5/(13.6e3 × 9.8) ≈ 0.76 m. So h = 760 mm. Standard barometric height.
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