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Two wires of same material (Y, ρ) and same length, one twice the diameter. Ratio of extensions under same load:
A4:1 (thinner stretches 4× more; A ∝ d²)
B1:4
C1:1
D2:1
Answer & Solution
Correct answer: A. 4:1 (thinner stretches 4× more; A ∝ d²)
ΔL = FL/(AY) ∝ 1/A ∝ 1/d². Doubling d gives 1/4 of extension. Ratio (thin:thick) = 4:1.
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