alleryTwo wires of same material (Y, ρ) and same length, one twice the diameter. Ratio of extensions under same load:
A4:1 (thinner stretches 4× more; A ∝ d²)
B1:4
C1:1
D2:1
Answer & Solution
Correct answer: A. 4:1 (thinner stretches 4× more; A ∝ d²)
ΔL = FL/(AY) ∝ 1/A ∝ 1/d².
Doubling d gives 1/4 of extension.
Ratio (thin:thick) = 4:1.
Keep practising Unit 2A: Newton's Laws and Translational Equilibrium
Browse all Unit 2A: Newton's Laws and Translational Equilibrium questions for AP Physics 1, or explore more Physics topics.
Related questions
At what temperature does kT equal 1 eV?A car travels 100 km at 50 km/h, then 100 km at 100 km/h. Average speed:Photon of wavelength 200 nm strikes metal with work function 2 eV. KE of fastest photoelecWork done in stretching wire by 1 mm is W. Work to stretch it by 2 mm (same wire, within eMagnetic flux through a coil changes from 5 mWb to 1 mWb in 0.1 s. Induced EMF:Bohr radius for hydrogen is 0.53 Å. Radius of 3rd orbit:Two coherent sources of intensity I and 4I interfere. Maximum intensity in resulting patteFor a body in SHM with amplitude A, at displacement x, ratio of KE to total energy: