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Crystal Field Stabilization Energy (CFSE) for high-spin d⁵ octahedral:
A+2 Δ_o
BZERO (3 × -0.4 + 2 × 0.6 = -1.2 + 1.2 = 0)
C-4 Δ_o
D-Δ_o
Answer & Solution
Correct answer: B. ZERO (3 × -0.4 + 2 × 0.6 = -1.2 + 1.2 = 0)
d⁵ high spin: t₂g³ e_g². CFSE = 3(-0.4 Δ_o) + 2(0.6 Δ_o) = 0. Result: d⁵ high spin has no CFSE (besides pairing energy considerations). All halides of high-spin d⁵ are colorless/pale, weakly stable.
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