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A toroid with 1000 turns and average radius 10 cm carries 0.5 A current. Field inside:
Aμ₀ × 1000 × 0.5 / (2π × 0.1)
Bμ₀ × 500
Cμ₀ × 1000
DZero
Answer & Solution
Correct answer: A. μ₀ × 1000 × 0.5 / (2π × 0.1)
B = μ₀ N I / (2π R). = (4π × 10⁻⁷)(1000)(0.5) / (2π × 0.1) = 2000π × 10⁻⁷ / 0.2π = 10⁻³ × 10 = 10⁻² × 0.1 = 10⁻³ T = 1 mT. (Magnetic field inside a toroid is essentially uniform.)
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