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Earth's magnetic field is approximately 50 μT. Force on a 1 m wire carrying 10 A perpendicular to field:
A5 × 10⁻⁴ N
B5 × 10⁻⁶ N
C50 N
D5 N
Answer & Solution
Correct answer: A. 5 × 10⁻⁴ N
F = BIL sin theta = (50 × 10⁻⁶)(10)(1)(1) = 5 × 10⁻⁴ N = 0.5 mN. Small but measurable.
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