A solenoid of 200 turns, length 0.5 m, carries 2 A. Find magnetic field inside (μ₀ = 4π × 10⁻⁷):
A1 × 10⁻³ T
B1 × 10⁻⁴ T
C5 × 10⁻⁴ T
D8π × 10⁻⁴ T
Answer & Solution
Correct answer: A. 1 × 10⁻³ T
n = 200/0.5 = 400 turns/m.
We have B = μ₀ n.
Then I = (4π × 10⁻⁷)(400)(2).
So I = 3200π × 10⁻⁷ ≈ 1 × 10⁻³ T.
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