alleryMagnetic field on the axis of a circular loop at distance x from center:
Aμ₀ I R² / [2(R² + x²)^(3/2)]
Bμ₀ I R / x
Cμ₀ I / (4π R)
Dμ₀ I R² / x³
Answer & Solution
Correct answer: A. μ₀ I R² / [2(R² + x²)^(3/2)]
B = μ₀ I R² / [2(R² + x²)^(3/2)] along the axis.
At center (x = 0): B = μ₀ I / (2R).
For x >> R: B ≈ μ₀ I R² / (2x³), like a magnetic dipole field.
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