In a survey, 60% read newspaper A, 40% read B, 20% read both. P(reading neither):
A10%
B20%
C30%
D40%
Answer & Solution
Correct answer: B. 20%
P(A or B) = P(A) + P(B) - P(A and B) = 60 + 40 - 20 = 80%. P(neither) = 1 - 80% = 20%.
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