Home › CA Foundation › Quantitative Aptitude › Binomial Theorem › Two coins are tossed. The probability of getting…
Two coins are tossed. The probability of getting two heads is
A1/4
B1
C1/3
D1/2
Answer & Solution
Correct answer: A. 1/4
1. Sample space S = {HH, HT, TH, TT}, total 4 outcomes.
2. Favourable = {HH}, count 1.
3. P(HH) = 1/4.
4. So the probability of two heads is 1/4.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.6_
Related questions
In the expansion of a bracket raised to four, the sum of indices is:How many terms are in the expansion of a bracket raised to twelve?How many terms are in the expansion of a bracket raised to five?In the last term of the expansion, the index of b is:In the first term of the expansion, the index of b is:In the first term of the expansion, the index of a is:The general rule for expansion is built using the concept of:Why is Pascal's triangle awkward for a large index?