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Three coins are tossed. The probability of getting at least one head is
A5/8
B3/8
C7/8
D1
Answer & Solution
Correct answer: C. 7/8
1. Total outcomes = 2^3 = 8.
2. P(no head) = P(TTT) = 1/8.
3. P(at least 1 head) = 1 - P(no head) = 1 - 1/8.
4. = 7/8.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.7_
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