Home › CA Foundation › Quantitative Aptitude › Binomial Theorem › Three coins are tossed. The probability of getti…
Three coins are tossed. The probability of getting at least one head is
A5/8
B3/8
C7/8
D1
Answer & Solution
Correct answer: C. 7/8
1. Total outcomes = 2^3 = 8.
2. P(no head) = P(TTT) = 1/8.
3. P(at least 1 head) = 1 - P(no head) = 1 - 1/8.
4. = 7/8.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.7_
Related questions
In the expansion of a bracket raised to four, the sum of indices is:How many terms are in the expansion of a bracket raised to twelve?How many terms are in the expansion of a bracket raised to five?In the last term of the expansion, the index of b is:In the first term of the expansion, the index of b is:In the first term of the expansion, the index of a is:The general rule for expansion is built using the concept of:Why is Pascal's triangle awkward for a large index?