For a Poisson distribution with mean λ = 3, P(X = 2):
A0.10
B0.224 (= λ²e⁻λ/2!)
C0.50
D0.50
Answer & Solution
Correct answer: B. 0.224 (= λ²e⁻λ/2!)
P(X = k) = e⁻λ λᵏ/k!. For λ = 3, k = 2: P = e⁻³ × 9/2 = 0.0498 × 4.5 ≈ 0.224.
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