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The van't Hoff factor i for a strong electrolyte like CaCl2 (full dissociation) is:
A3
B4
C1
D2
Answer & Solution
Correct answer: A. 3
CaCl2 → Ca²⁺ + 2Cl⁻, giving 3 ions per formula unit. So i = 3. For NaCl, i = 2. For Al2(SO4)3, i = 5.
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