Start learning →

For a 1 m glucose aqueous solution (i = 1), boiling point:

A100.52°C (using K_b water = 0.52 K kg/mol)
B100°C
C101°C
D99.48°C
Answer & Solution
Correct answer: A. 100.52°C (using K_b water = 0.52 K kg/mol)
ΔT_b = K_b × m × i = 0.52 × 1 × 1 = 0.52 K. New BP = 100 + 0.52 = 100.52°C.
Practise this question with Quill — JEE Advanced →

Keep practising Unit 3B1: Solutions and Concentrations

Browse all Unit 3B1: Solutions and Concentrations questions for JEE Advanced, or explore more Chemistry topics.

Start a Unit 3B1: Solutions and Concentrations lesson →