For the same angle with tan x = -3/4 in quadrant II, what is cos(2x)?
A-7 / 25
B-24 / 25
C7 / 25
D24 / 25
Answer & Solution
Correct answer: C. 7 / 25
1. From the reference triangle, sin x = 3/5 and cos x = -4/5.
2. Apply cos(2x) = cos^2 x - sin^2 x.
3. The first square is (-4/5)^2 = 16/25.
4. The second square is (3/5)^2 = 9/25.
5. Subtracting gives 16/25 - 9/25 = 7/25.
6. The result is positive because squaring removes the sign the second quadrant put on the cosine.
7. Choosing -7/25 amounts to computing sin^2 x - cos^2 x, which reverses the order of subtraction.
_Source: OpenStax Algebra and Trigonometry (CC BY 4.0), Ch 9 "Trigonometric Identities and Equations", section 9.3 Double-Angle, Half-Angle, and Reduction Formulas_
Keep practising Trigonometric Identities and Equations
Browse all Trigonometric Identities and Equations questions for B.Sc Mathematics, or explore more Mathematics topics.
Related questions
If a ladder's base is a feet from the wall and its length is 4a feet, how high up the wallSafety rules place a ladder's base 1 foot from the wall for every 4 feet of ladder length.Compared with y = sin t, the graph of y = sin(2t) is which transformation?Solving sin(n t) = c across one turn requires going around the unit circle how many times?Solve cos(2t) = 1/2 on the interval from 0 to 2 pi.Solve 3 cos t + 3 = 2 sin^2 t exactly on the interval from 0 to 2 pi.Solve cos t cos(2t) + sin t sin(2t) = sqrt(3)/2 on the interval from 0 to 2 pi.Solve 2 sin^2 t + sin t = 0 exactly on the interval from 0 to 2 pi.