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Verifying (sec^2 x - 1) / sec^2 x = sin^2 x by splitting the fraction gives which intermediate expression?

Atan^2 x - 1
Bcos^2 x - 1
C1 - cos^2 x
D1 + cos^2 x
Answer & Solution
Correct answer: C. 1 - cos^2 x
1. Split the single fraction into sec^2 x / sec^2 x minus 1 / sec^2 x. 2. The first piece is simply 1. 3. The second piece uses the reciprocal identity 1 / sec^2 x = cos^2 x. 4. So the expression becomes 1 - cos^2 x. 5. Rearranging sin^2 x + cos^2 x = 1 gives 1 - cos^2 x = sin^2 x, which is the target. 6. The option cos^2 x - 1 reverses the subtraction and equals minus sin^2 x, so it carries the wrong sign. 7. The option 1 + cos^2 x adds instead of subtracting and can reach 2, which sin^2 x never does. _Source: OpenStax Algebra and Trigonometry (CC BY 4.0), Ch 9 "Trigonometric Identities and Equations", section 9.1 Solving Trigonometric Equations with Identities_
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