If factoring and substitution both fail while verifying an identity, what is the recommended fallback?
AConvert every term to sines and cosines
BConvert every term to secants and cosecants
CDifferentiate both sides and compare them
DReplace the variable with a special angle
Answer & Solution
Correct answer: A. Convert every term to sines and cosines
1. The verification routine is to work one side, look for factoring or a squared binomial, then match functions to known identities.
2. When none of that lands, rewrite every term using only sine and cosine.
3. Sine and cosine are the two functions all the others are defined from, so the equation becomes purely algebraic.
4. Substituting a special angle only tests one value and never verifies an identity, which must hold across the whole domain.
_Source: OpenStax Algebra and Trigonometry (CC BY 4.0), Ch 9 "Trigonometric Identities and Equations", section 9.1 Solving Trigonometric Equations with Identities_
Keep practising Trigonometric Identities and Equations
Browse all Trigonometric Identities and Equations questions for B.Sc Mathematics, or explore more Mathematics topics.
Related questions
If a ladder's base is a feet from the wall and its length is 4a feet, how high up the wallSafety rules place a ladder's base 1 foot from the wall for every 4 feet of ladder length.Compared with y = sin t, the graph of y = sin(2t) is which transformation?Solving sin(n t) = c across one turn requires going around the unit circle how many times?Solve cos(2t) = 1/2 on the interval from 0 to 2 pi.Solve 3 cos t + 3 = 2 sin^2 t exactly on the interval from 0 to 2 pi.Solve cos t cos(2t) + sin t sin(2t) = sqrt(3)/2 on the interval from 0 to 2 pi.Solve 2 sin^2 t + sin t = 0 exactly on the interval from 0 to 2 pi.