alleryA parallel-plate capacitor in vacuum has plate area A and separation d. Its capacitance is
Aε₀ A d
BA / (ε₀ d)
Cε₀ A / d
Dε₀ d / A
Answer & Solution
Correct answer: C. ε₀ A / d
1. For a parallel-plate capacitor, σ = Q / A and E = σ / ε₀.
2. V between plates = E × d = Q d / (ε₀ A).
3. C = Q / V = ε₀ A / d.
_Source: syllabus Physics Part I, Ch 2 §2.12_
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