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Which of the following octahedral complexes can exhibit **geometric (cis/trans)** isomerism?
A$[Co(NH_3)_6]^{3+}$ (homoleptic)
B$[Co(NH_3)_4Cl_2]^+$ (MA₄B₂ type)
C$[Co(en)_3]^{3+}$
D$[Pt(NH_3)_4]^{2+}$ (square planar, all same)
Answer & Solution
Correct answer: B. $[Co(NH_3)_4Cl_2]^+$ (MA₄B₂ type)
Octahedral MA₄B₂-type complexes can have cis (both B adjacent) or trans (both B opposite) arrangements. MA₆ (homoleptic) has only one geometry; tris-bidentate M(en)₃ shows only optical isomers; MA₄ square planar with all same ligands has no isomers.
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