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If the current in a primary coil changes at 30 A/s and induces 0.6 V in a secondary coil, the mutual inductance is:
A0.02 H
B0.05 H
C2.0 H
D0.2 H
Answer & Solution
Correct answer: A. 0.02 H
$|e_2| = M \cdot |dI_1/dt|$ ⇒ $M = 0.6/30 = 0.02$ H = 20 mH.
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