alleryIf the current in a coil of inductance 5 H changes from 2 A to 5 A in 0.1 s, the magnitude of induced EMF is:
A50 V
B100 V
C300 V
D150 V
Answer & Solution
Correct answer: D. 150 V
$|e| = L\,|dI/dt| = 5 \times (5-2)/0.1 = 5 \times 30 = 150$ V.
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