alleryA coil of self-inductance 2 H carries a current of 4 A. The energy stored in its magnetic field is:
A4 J
B16 J
C8 J
D32 J
Answer & Solution
Correct answer: B. 16 J
$U = \tfrac{1}{2} L I^2 = \tfrac{1}{2}(2)(4^2) = 16$ J.
Keep practising Electromagnetic Induction
Browse all Electromagnetic Induction questions for AP Intermediate 2nd Year, or explore more Physics topics.
Related questions
SI unit of magnetic flux is:Lenz's law states the induced current direction is such that it:Faraday's law of electromagnetic induction states EMF induced equals:The energy stored per unit volume in a magnetic field $B = 0.1$ T in vacuum (take $\mu_0 =If the current in a primary coil changes at 30 A/s and induces 0.6 V in a secondary coil, If the current in a coil of inductance 5 H changes from 2 A to 5 A in 0.1 s, the magnitudeTwo inductors of 4 H and 12 H are connected in **parallel** (no mutual inductance). The eqWhen two inductors $L_1$ and $L_2$ are connected in **series** (no mutual inductance), the